Hi Gioak,

this was just a suggestion so that you can easily familiarize yourself with the basics, as this can be helpful in learning EasyLanguage. Once you have the simple code working, you can easily adapt it to what you have in mind.

Regards,

ABCTG

You can create an array to store the value (highest high for the last 6 bars) for every bar.

Then at a later time you can call up the X place in the array to see the highest bar for that (6 bar) subset.

If you are worried about nanoseconds in your code, this might not be the most efficient way, but it is an easy way to code.

If I remember well you have the functions HHV and LLV in easylanguage.
So the highest high of the last 5 bars would be HHV( H, 5 ), the lowest low LLV( L, 5 ),
the highest open HHV( O, 5 ) etc.

Kolnidrei,

HHV and LLV are part of Metastock as far as I am aware, but maybe someone created them for Tradestation as custom functions, too. However you can accomplish the same using the built-in functions Highest and Lowest i.e. Highest( High, 5 ) would give you the highest high over the last five bars in EasyLanguage.

Regards,

ABCTG

Kolnidrei 

If I remember well you have the functions HHV and LLV in easylanguage. So the highest high of the last 5 bars would be HHV( H, 5 ), the lowest low LLV( L, 5 ), the highest open HHV( O, 5 ) etc.

Hi Gioak,

hh will be the value you want.
hh_barsback will be the location (bars back).

 

Code

var: hh(0), hh_barsback(0); hh = 0; for k = 0 to N-1 begin if Low[k] < x and High[k] > hh then begin hh = High[k]; hh_barsback = k; end; end;

Hi edgefirst, thank you for your suggestion.. but my difficulty was in coding the command to find highest (high, 5) only among the bars previous to the current bars that have a minimum lower than the level x, that is the high of the current bar.

Gioak

Hi Gioak,

this is exactly what the code @edgefirst posted provides, just replace x with High.
You would also have to make k a variable and N could be an input with the value of 5.

Regards,

ABCTG

cactus1973 

Hi edgefirst, thank you for your suggestion.. but my difficulty was in coding the command to find highest (high, 5) only among the bars previous to the current bars that have a minimum lower than the level x, that is the high of the current bar. Gioak

Hi ABCTG ,
I have elaborated the code following the instructions but as you can see from the output HH is not calculated, I suppose something is wrong;

input: N(4);
var:Lsetup(0), K(0), hh_barsback(0),hh(0);

IF D > D[1]then begin

Lsetup = 0;
If C < L[1] and L = lowest(low,5) then Lsetup = H ;
end;

HH = 0;
for k = 0 to N-1 begin
if Low[k] < Lsetup and High[k] > hh then begin
HH = High[k];
hh_barsback = k;
end;
end;

print(File("C:\Users\utente\Desktop\outputMulticharts\test.txt")," symbol ",symbol," date ",date:7:0,spaces(2)," time ",time:4:0,spaces(2)," spaces(3)," lsetup ",lsetup,spaces(3)," hh ",hh);

Hi Gioak,

check your values for Lsetup as they might prevent the code from finding values on bars you are checking.

It might make sense to take one step back by removing the "Low[k] < Lsetup" to confirm that the code is able to find the highest high within the lookback.
Once you know that this part is working correctly you can proceed in tracking down what is not working correctly when you re-introduce "Low[k] < Lsetup" to your rules.

Regards,

ABCTG

cactus1973 

Hi ABCTG , I have elaborated the code following the instructions but as you can see from the output HH is not calculated, I suppose something is wrong; input: N(4); var:Lsetup(0), K(0), hh_barsback(0),hh(0); IF D > D[1]then begin Lsetup = 0; If C < L[1] and L = lowest(low,5) then Lsetup = H ; end; HH = 0; for k = 0 to N-1 begin if Low[k] < Lsetup and High[k] > hh then begin HH = High[k]; hh_barsback = k; end; end; print(File("C:\Users\utente\Desktop\outputMulticharts\test.txt")," symbol ",symbol," date ",date:7:0,spaces(2)," time ",time:4:0,spaces(2)," spaces(3)," lsetup ",lsetup,spaces(3)," hh ",hh);

ABCTG 

Hi Gioak, check your values for Lsetup as they might prevent the code from finding values on bars you are checking. It might make sense to take one step back by removing the "Low[k] < Lsetup" to confirm that the code is able to find the highest high within the lookback. Once you know that this part is working correctly you can proceed in tracking down what is not working correctly when you re-introduce "Low[k] < Lsetup" to your rules. Regards, ABCTG

I've tried but I think the code has some problem finding the highest high, it does not calculate hh.

If D > D[1]then begin

Lsetup = 0;
If C < L[1] and L = lowest(low,5) then Lsetup = H ;
end;

input: N(4);
var: K(0), hh_barsback(0),hh(0);


HH = 0;
for k = 0 to N-1 begin
if {Low[k] < Lsetup and} High[k] > hh then begin
HH = High[k];
hh_barsback = k;
end;
end;
print(File("C:\Users\utente\Desktop\outputMulticharts\test.txt")," symbol ",symbol," date ",date:7:0,spaces(2)," time ",time:4:0,spaces(2)," lsetup ",lsetup,spaces(3)," hh ",hh);


Regards,

Gioak