Question about : GANN SQUARE  Help Please ? 
September 27th, 2012, 06:29 AM  #1 (permalink) 
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Question about : GANN SQUARE  Help Please ?
I'm having a problem with navigating around a Gann square. Its
especially frustrating because it seems like the solution I am after should be very simple and yet it is eluding me. I have found online a number of sites that say that a certain method will work and yet I have tried it and it clearly does not, or at least it does not work entirely the way its claimed. For example, this site, among many others ; sacredscience dot com/ferrera/gannwheel dot htm States the following (please see my continuation of my message after the below quotes ( " ) and ( .... ) ; ........... "Basically, if you want to move around the coordinates on the Gann Wheel you take the number you are interested in ( such as the all time High or Low price) take the square root of the number, then add or subtract 2 from the root and resquare the result. Example: Lets say that we are interested in the price 664 (which is in the vertical column straight up from the center). The square root is 25.768 + 2 = 27.768^2 = 771 which is the number directly above 664 or one full 360 degree cycle out from center. If we subtracted 2 from the root and resquared the number (25.7682= 23.768^2 = 565 ) we would get 565 which is directly below 664 or one full 360 degree cycle in towards center. Incorporating the Gann Emblem with this technique, allows us to calculate coordinates that are conjunct (360 = +/ 2 from the root), opposition (180 = +/ 1 from root #), trine (120= +/ .666) (240= +/ 1.333), square (90 = +/ .5) (270= +/ 1.5) sextile (60 = +/ .333) (300 = +/ 1.666). This technique is extremely useful for finding coordinate squares on the Gann Wheel that are making hard aspects to a previous position on the wheel. Also, Gann believed that the numbers that connected the square base of the pyramid (the 4 corners of the square, i.e. corner #’s.) to the “gravity center” and also the numbers that ran straight vertical and horizontal from the “gravity center” in the form of a cross (cardinal numbers) were very important in balancing “Price & Time” on the wheel." .............. So I tried all of the above, and the only part that worked was the first one, the conjunct ; conjunct (360 = +/ 2 from the root), None of the others worked at all, and certainly not with consistency. See attached graphic. Basically what I want to do, is described in Figures (A,B,C) of the graphic. Regardless of the number placed in the center of the square grid, Id like to be able to go to any given square in a given grid and then from that grid cell be able to orient in any angular direction outwards and to any nth square. I can do this easily enough for the conjunct, for example, note the green arrows in figures A,B,C All I have to do is change ; conjunct (360 = +/ 2 from the root), to conjunct (360 = +/ 4,6,8,16,32 from the root), to get the next cell in any nth square vertically up or down However if I want to find any value outwards on angles of 45, 90, 180, 30, 60, 120 Note the the orange and red arrows for example I cant get accurate or even close values consistently to be derived. There must be some way to find out for instance, using the Gann Square, what the first, second, third, etc... order of value is at say 60 degrees outward from any value placed in the center grid There must also be some way to select any given cell coordinate on the grid, and then from that cell, from any angle outwards find out what the first, second, third, value is for any nth square radiating outward from that point would be. Can someone help me with this? I've looked everywhere and it must be a simple solution? 