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Question going by tick
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Created: by jeffbg123 Attachments:0

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Question going by tick

  #1 (permalink)
Elite Member
Futures Experience: Advanced
Platform: Other
Posts: 35 since Feb 2010
Thanks: 3 given, 1 received

Question going by tick

I am new to NinjaTrader but know C# and need some advice.

I want to run a strategy that relies on the previous 2 5000 tick bars. However I don't really want to do it by bar, I want to have a moving window of the last 5000 ticks and the 5000-10000th ticks. So what I was doing is just keeping a list of my own of these ticks.

public class scalper : Strategy
List<double> barFar = new List<double>();
List<double> barNear = new List<double>();

protected override void Initialize()
            CalculateOnBarClose = false;
            EntryHandling        = EntryHandling.UniqueEntries;

protected override void OnBarUpdate()
double curPrice = Close[0];
            while(barNear.Count > ticksTimeFrame)
            while(barFar.Count > ticksTimeFrame)
            List<double> barFarCopy = new List<double>(barFar);
            List<double> barNearCopy = new List<double>(barNear);
            if(barFar.Count == ticksTimeFrame && barNear.Count == ticksTimeFrame)
                double barNearMid = Math.Min(barNearCopy[0], barNearCopy[barNearCopy.Count - 1]) + Math.Abs(barNearCopy[0] - barNearCopy[barNearCopy.Count - 1]);

                double barFarMid = Math.Min(barFarCopy[0], barFarCopy[barFarCopy.Count - 1]) + Math.Abs(barFarCopy[0] - barFarCopy[barFarCopy.Count - 1]);
Will this just keep the last 2 windows of ticks and find their middle price?


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  #2 (permalink)
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  #3 (permalink)
Trading for Fun
Dallas TX/USA
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jeffbg123 View Post
Will this just keep the last 2 windows of ticks and find their middle price?

well you generally don't need to copy and then sort 10k-sized lists on every tick when all you want is the average of their largest and smallest values. As a first step you can just scan the list and locate the high and low in O(n) time. If you'd like to do better than that, I've written up an algorithm for maintaining a sorted sliding window with expected O(n/2) performance, which is article #5 on this page: Move the Markets| Articles.

I guess I wasn't totally clear on if you wanted the median, or the midpoint. Assuming the latter, then you'd want (H+L)/2... but as far as I can tell your code doesn't do that. It seems to be calculating Min(L, L + Abs(L - H))... which would always evaluate to L.

Hope this helps.

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