Coding help

January 27th, 2014, 09:24 AM

I have some code below for TS which utilizes a displaced slowMA. How would I replace this displaced slowMA with a displaced low band of a keltner channel? This one is taxing my brain!!

Thanks

Pi

inputs:
Extension1_Percent(200),
Extension2_Percent(250),
ExtensionColor(red),
ExtensionColorMove(darkre d),
ShowExtensionHistory(true ),
LineLength_Bars(4),
SlowAvgPrice(close),
SlowAvgLength(10),
SlowAvgDisplace(3),
FastAvgPrice(close),
FastAvgLength(5);

variables:
Debug(false),
StartSwitch(false),
SecondSwitch(false),
ThirdSwitch(false),
OriginalLow(0),
Counter(0),
Projection1(0),
Projection2(0),
SlowAverage(0),
FastAverage(0),
TLForeCast(0),
LowBar(99999999),
TL(-1);

//========================= =========
// Calcluation Module
//========================= =========
Once TL = TL_New(Date,Time,0,Date,T ime,0); //Initialized TrendLine
SlowAverage = WAverage(SlowAvgPrice, SlowAvgLength);
FastAverage = WAverage(FastAvgPrice, FastAvgLength);
Counter += 1;
if date <> date[1] then begin //reset conditions on start of day
StartSwitch = false;
SecondSwitch = false;
ThirdSwitch = false;
end;

if SlowAvgDisplace >= 0 or CurrentBar > AbsValue(SlowAvgDisplace) then begin

ABCTG · January 27th, 2014, 10:34 AM

Pitrader,

your code doesn't show where the displacement is done, but the code for a lower Keltner band is this:

Code

inputs:  KeltnerPrice( Close ), KeltnerLength( 20 ), KeltnerNumATRs( 1.5 ), KeltnerDisplace( 0 ) ;
variables:  KeltnerMidline( 0 ), KeltnerATR( 0 ), LowerKeltnerBand( 0 );

KeltnerMidline = AverageFC( KeltnerPrice, KeltnerLength ) ;
KeltnerATR = KeltnerNumATRs * AvgTrueRange( KeltnerLength ) ;
LowerKeltnerBand = KeltnerMidline - KeltnerATR ;

if KeltnerDisplace >= 0 or CurrentBar > AbsValue( KeltnerDisplace ) then
	Plot1[KeltnerDisplace]( LowerKeltnerBand, "LowerBand" ) ;

Regards,
ABCTG

January 28th, 2014, 07:52 PM

Thanks for the info ABCTG. I will give it a shot and let you know how it worked out.

Cheers

Pi

January 29th, 2014, 06:22 PM

Hey ABCTG everything worket out.

Thanks again.

Pi

ABCTG · January 30th, 2014, 09:12 AM

Pi,

you are welcome and thanks for letting me know.

Regards,
ABCTG

Coding help

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Coding help