San Jose, CA
Experience: Intermediate
Platform: Zaner360
Broker: DeCarley/Zaner/Gain
Trading: NG,6E
Posts: 18 since Aug 2018
Thanks Given: 30
Thanks Received: 14
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Hi all,
I'm reading Tharp's "Trade your way to financial freedom" and in chapter 10 (pg 296) he covers the idea of Sweeney's Maximum Adverse Excursion (MAE). I believe I understand what MAE is, but I don't understand his examples, either the chart one, or the table one. I was hoping someone could help explain what I'm missing from Tharp's explanation.
Here's what I understand from MAE, for example:
* Say you enter a corn position short at 450.00, with a stop at 460.
* Say the contract moved to 457 then you exited for a profit at 442.
* Your MAE would be 7 cents (450-457). Your initial risk is 10 cents (450-460).
* Your MAE would be 0.7R.
From what I understand, you should never have an MAE that exceeds 1R (except in cases of slippage) and your loss cannot (ever) be larger than your MAE. In general, MAE should be between 0 and 1 R.
However, in Table 10.1 (below), Tharp has multiple examples where the loss is greater than MAE and one case where MAE is >1R. How is that possible?
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